Take-home Exam 1: Mini-projects
CHEM 291-A · Chemical Thinking
Four projects, in increasing difficulty. Each of you completes only the one project assigned to you by email — check your inbox for your project number. The in-class test is separate. All data below are synthetic teaching data. No differentiation, determinant, or matrix inverse is required.
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Project 1: The sample that looks too dark
LEVEL 1 · EASY
Chemical question: Can you report both unknown concentrations without using a calibration beyond the range tested?
Recognition prompts
- What do the standard solutions hold fixed, and what changes from vial to vial?
- Why does adding water change concentration but not the amount of solute?
- Which observed quantity is an instrument reading, and which is the chemical quantity you want?
A colorimeter was calibrated with five known concentrations of one dissolved dye. Absorbance is dimensionless. The numbers below are simulated, chosen so you can examine the reasoning.
| Concentration (mM) | 0.0 | 1.0 | 2.0 | 3.0 | 4.0 |
| Absorbance | 0.020 | 0.160 | 0.300 | 0.440 | 0.580 |
Unknown U: absorbance 0.370. Unknown V: absorbance 0.720. Equal volumes of V and pure water are then mixed; the diluted V reads 0.370.
- Make the observation visible. Plot the five standards as absorbance versus concentration; mark U and the undiluted V as horizontal reading levels.
- Build the simplest useful model. Find the slope and baseline, with units where appropriate. Write absorbance as a function of concentration and verify one standard you did not use to find the slope.
- Find the unknowns. Determine U from its reading. Determine V from its diluted reading, explicitly showing the dilution calculation.
- Make a decision. Explain why calculating a number from V = 0.720 using the line does not, by itself, justify reporting it as calibrated.
- Test your answer. Predict the absorbance of the diluted V from your reported original concentration and explain why U and diluted V can have identical readings.
Limit: Use only the measured standard range to claim calibration validity; model extrapolation is a different claim.
Project 2: The reaction that halves
LEVEL 2 · EASY+
Chemical question: What mathematical description explains a constant fractional loss, and when is a short polynomial an acceptable shortcut?
Recognition prompts
- Do equal five-minute intervals remove equal amounts or equal fractions?
- What does a straight line hide or reveal when you change what is on the vertical axis?
- Why should a local approximation be checked before using it for a longer time?
A dissolved species A disappears during a simplified reaction. The following simulated concentration observations are exact for this teaching model.
| Time (min) | 0 | 5 | 10 | 15 |
| [A] (M) | 0.800 | 0.400 | 0.200 | 0.100 |
For this project, use the model [A](t) = [A]0 exp(−kt). Use a dimensionless ratio inside the logarithm. An exponent of −0.10 corresponds to a short time interval Δt = 0.10/k. Compare exp(−0.10) with 1 − 0.10 and 1 − 0.10 + (0.10)²/2.
- Recognize the pattern. Compute successive differences and successive ratios. Decide whether a straight line in ordinary [A] versus time is a suitable model.
- Change the representation. Plot or tabulate ln([A]/[A]0) against time. Extract k, state its units, and explain the meaning of the negative slope.
- Predict. Estimate [A] at 12 min from the model; check that your prediction lies between the 10- and 15-minute observations.
- Approximate locally. Evaluate the linear and quadratic approximations to exp(−0.10), compare each to your calculator, and decide which achieves absolute error below 0.001.
- State a boundary. Explain why an approximation tested at −0.10 should not be assumed accurate at −2.
Limit: These data support a useful mathematical model; they do not independently prove a molecular reaction mechanism.
Project 3: The dipole and the fixed meter
LEVEL 3 · EASY–MEDIUM
Chemical question: Why can turning an unchanged molecule change what a fixed directional sensor measures?
Recognition prompts
- Which parts of the molecular description are lengths, and which are directions?
- Does changing the direction of the whole molecule change its internal geometry?
- If the meter and molecule both turn together, what should remain the same?
Model water in a 2-D drawing: O = (0,0), H1 = (0.80, 0.60) Å, H2 = (0.80, −0.60) Å. Assign each O→H bond a dipole contribution of magnitude 1.50 D, directed along its bond. This is an idealized vector model, not a measured water dipole.
| Object | x coordinate / component | y coordinate / component |
| O | 0.00 Å | 0.00 Å |
| H1 | +0.80 Å | +0.60 Å |
| H2 | +0.80 Å | −0.60 Å |
The meter reads the dot product of the total dipole with a fixed unit sensing direction ex = (1,0). The molecule is rotated 90° counterclockwise using the matrix R = [[0, −1], [1, 0]].
- Draw before computing. Sketch both O→H vectors, their individual dipole contributions, and the fixed +x meter direction.
- Add the physical contributions. Find each bond unit vector, each bond dipole vector, and the total dipole μ. Give components and magnitude in D.
- Let a matrix act. Multiply Rμ. Then separately compute Rμ1 + Rμ2 and compare with R(μ1 + μ2).
- Ask what the meter reads. Compute μ·ex before rotation and (Rμ)·ex after rotation.
- Test what stays the same. Check the dipole magnitude before and after; now rotate the sensing direction by R too and recompute the dot product. Explain the difference between turning the molecule and merely redescribing the same geometry.
Limit: No 3-D rotation formula is needed. The 2-D model isolates the role of direction and representation.
Project 4: Two colors, two readings
LEVEL 4 · MEDIUM
Chemical question: When two substances both affect both signals, can two instrument readings distinguish their amounts?
Recognition prompts
- What is mixed physically, and what is mixed in the instrument response?
- Why can the reading at one wavelength be explained by several different mixtures?
- What does the row-by-column product actually calculate?
A sample contains dyes P and Q. A detector reads absorbance at wavelengths λ1 and λ2. For this simulated linear model, the calibration sensitivities (in mM−1) are:
| Wavelength | Effect of 1 mM P | Effect of 1 mM Q |
| λ1 | 0.40 | 0.10 |
| λ2 | 0.15 | 0.30 |
Three prepared controls contain (P,Q) in mM: C1 = (2,0), C2 = (0,2), C3 = (2,1). A blinded mixture produces the readings (A1, A2) = (0.90, 0.60). Absorbance is dimensionless.
- Draw the coupling. Sketch arrows from both dyes to both wavelength readings; explain why a single calibration line for P would not suffice.
- Represent the mapping. Form the 2×2 sensitivity matrix M and a 2×3 concentration matrix C whose columns are the three controls. Label rows, columns, and units.
- Multiply with meaning. Compute MC by row-by-column multiplication. Explain one product entry in a complete chemical sentence.
- Solve the blind mixture. Write the two simultaneous equations and solve by substitution or elimination. Verify your concentrations by multiplying M by your result.
- Expose a tempting error. If you pretend Q does not absorb at λ1, what P concentration would you report? Compare it with the two-wavelength result and explain the discrepancy.
Limit: Stay within matrix multiplication and two simultaneous linear equations. Matrix inverse and determinant are not needed.
Submit (for your assigned project): a 1–2-page scientific note with a graph/diagram, model, reproducible calculation, independent check, and chemical interpretation. Reply to your assignment email with your note as a PDF.
Marking guide (20 points): recognition 4 · representation 4 · calculation 6 · check/limitation 4 · communication 2.