Appendix F — Problem Set 4 | DIRECTION: Vectors and Bonds
Companion to §2.1–2.2 — direction and magnitude
A. Recognition
1. Scalar or vector?
Classify each quantity and justify one borderline case.
- temperature
- molecular dipole moment
- bond length
- force on a nucleus
- activation energy
- concentration gradient
- reaction rate in \mathrm{mol\,L^{-1}\,s^{-1}}
2. What operation is needed?
Choose vector addition, subtraction, scalar multiplication, magnitude, or normalization.
- Find a bond vector from two atomic positions.
- Combine three bond dipoles.
- Retain direction but discard magnitude.
- Compare the length of a computed displacement with experiment.
- Reverse a force while doubling its strength.
B. Components and geometry
3. Bond vector and unit vector
In Cartesian coordinates, \mathbf r_C=(1.20,-0.40,0.10)\ \text{Å} and \mathbf r_O=(2.35,0.25,-0.55)\ \text{Å}.
- Find the vector from C to O.
- Find the C–O bond length.
- Find the unit vector pointing from C to O.
- Confirm that the unit vector has magnitude 1 within rounding.
4. Coordinate translation test
Translate both positions in Problem 3 by \mathbf a=(-4.0,2.0,1.5)\ \text{Å}.
- Write the translated coordinates.
- Recalculate the C-to-O vector.
- State and verify the invariant.
5. Resultant molecular dipole
Three bond-dipole contributions, in debye, are \boldsymbol\mu_1=(1.20,0,0),\quad \boldsymbol\mu_2=(-0.35,0.95,0),\quad \boldsymbol\mu_3=(-0.35,-0.20,0.60).
- Calculate the total molecular dipole vector.
- Calculate its magnitude.
- A model reports only the sum of the three magnitudes. Explain why that is generally wrong.
6. Force from a potential
Along one coordinate, U(x)=\tfrac12k(x-x_0)^2, with k=500\ \mathrm{N\,m^{-1}} and x-x_0=2.0\times10^{-12}\ \mathrm m.
- Use F_x=-dU/dx to derive the force.
- Calculate its value and direction.
- Repeat for x-x_0=-2.0\times10^{-12}\ \mathrm m.
- What physical role does the minus sign play?
C. Chemical models
7. Water from two bond vectors
Model two equal O–H bond dipoles of magnitude \mu_b=1.50\ \mathrm D, separated by 104.5^\circ. Place their bisector along +y.
- Write both dipoles in components using half the bond angle.
- Show which components cancel.
- Calculate the resultant magnitude.
- Predict the effect of changing the angle toward 180^\circ while holding \mu_b fixed.
8. Carbon dioxide cancellation
Represent the two equal C=O bond dipoles of linear CO_2 as vectors.
- Show algebraically why their sum is zero.
- Explain why “CO_2 has polar bonds” does not imply “CO_2 has a molecular dipole.”
- If one bond dipole were 1.0% larger, express the residual dipole in terms of \mu_b.
9. Center of mass as a weighted vector sum
For three atoms with masses m_i and positions \mathbf r_i, derive \mathbf R_{CM}=\frac{\sum_i m_i\mathbf r_i}{\sum_i m_i}. Then calculate \mathbf R_{CM} for atoms of mass 12, 1, and 16 u at (0,0,0), (1,0,0), and (0,1,0) Å.
10. Error diagnosis
A student normalizes \mathbf v=(3,4,0) by dividing every component by 3+4+0.
- Test whether the result has unit magnitude.
- Correct the normalization.
- Explain the difference between component sum and Euclidean magnitude.